Placement Aptitude Test | Check Your Rank | Free Practice!
This mock test is designed to mimic placement aptitude tests for engineering students. Attempt the test, check your ranking, and invite your friends to join as well.
Section 1: Quant
Section 2: Reasoning
Section 3: Verbal
Leaderboard
| Rank | Name | College | Quant | Reasoning | Verbal | Final Score |
|---|---|---|---|---|---|---|
| ๐ฅ | MS | NM | 10 | 7 | 10 | 27 |
| ๐ฅ | Satyajeet Kumar | NIT Rourkela | 10 | 5 | 10 | 25 |
| ๐ฅ | Ayush Raj | IIT K | 9 | 6 | 9 | 24 |
| 4 | Kanishk | JSSATE | 10 | 6 | 8 | 24 |
| 5 | Aditya | IIT BHU | 9 | 6 | 9 | 24 |
| 6 | S k | iit d | 10 | 7 | 7 | 24 |
| 7 | Jash | IIT BHU | 10 | 5 | 8 | 23 |
| 8 | Professional | XYZ | 10 | 6 | 7 | 23 |
| 9 | Jxjcj | Bxjx | 10 | 6 | 6 | 22 |
| 10 | SPARSH | FORE | 9 | 7 | 5 | 21 |
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Solutions
Please note that order might be different as questiosn ae randomized in the test
Quant Solutions
Sol : 1
Original Price = 200
Price after a 20% increase = 200+(20% of 200)=200+40=240
Price after a 10% discount on 240 = 240โ(10% of 240)=240โ24=216
Sol : 2
A=$5000 * (1+8/100โ)^2 = 5000*(1.08)^2$
= 5000ร1.1664 = 5832$
Sol : 3
Based on given ration, let number of boys, girls and teachers be 33x, 53x and 2x.
Given, 2x=10, so x=5
Number of students = (33x + 53x)=86ร5=430
Sol : 4
Loss = CP – SP = 5400 – 4500 = 900
Loss % = 900/ 5400*100 = 16.67%
Sol: 5
Subtracting the two equations:
$x+y – (xโy)=12 – 4$
$2y = 8$
$y = 4$
Sol : 6
Let the five consecutive numbers be xโ2, xโ1, x, x+1 and x+2
Their average = x=15
Smallest number = xโ2=13; and largest = x+2=17
Sum of smallest and largest = 13+17 = 30
Sol: 7
Convert the speed into km/hr first
Speed = 30m/s = 30*3600/1000 = 108 km/hr
Time = 240/108 = 2.22 hour
Sol : 8
Total work = 6 menร8 days=48 man-days
For 4 men, days required = 48 /4 =12
Sol : 9
Use direct formula of area of circle = $\pi*r^2$
Sol: 10
Number of arrangements = 4!
Reasoning Solutions
Sol : 1
Z (26), Y (25), W (23), T (20), P (16)
The pattern is: -1, -2, -3, -4
Following the pattern, the next term will be Pโ5=M
Sol : 2
Every letter is increased by 1
Sol : 3
The man is the son of Sarahโs mother or father, which makes him Sarah’s brother.
Sol : 4
The problem states a clear requirement of 5 years of experience. Although Jane has the required qualification, she lacks the experience, so based on the strict criteria, she should not be selected.
Sol : 5
The statement implies that planning aids in success, but it doesnโt imply exclusivity. Hence, assumption B is correct.
Sol : 6
U is second from the right, so position 5 is U.Since Q is between P and R, and S is to the left of T, the order is:
P – Q – R and S – T – U
With U in the fifth position, R must be on the right end (position 6).
Sol : 7
2024 is a leap year, so it has 366 days.
From February 15, 2024, to February 15, 2025, there are 366 days.
366 days = 52 weeks + 2 extra day. Thus, the day will shift by 2 days
Sol : 8
Starting at south, turns go as follows:
- Right to west
- Left to south
- Left to east
So, Sarah is facing east.
Sol : 9
Dots are moving by 90 degree in each step
Sol : 10
Assume B has x apples, A will have x + 4 and C will have 2x.
Solve to get x = 6
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