Placement Aptitude Test | Check Your Rank | Free Practice!

This mock test is designed to mimic placement aptitude tests for engineering students. Attempt the test, check your ranking, and invite your friends to join as well.

Section 1: Quant

Section 1: Quantitative Aptitude (Placement Mock Test)

  • 10 Qs | 10 Marks | 10 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Section 2: Reasoning

Section 2: Logical Reasoning (Placement Mock Test)

  • 10 Qs | 10 Marks | 10 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Section 3: Verbal

Section 3: Verbal Ability (Placement Mock Test)

  • 10 Qs | 10 Marks | 5 Mins
  • No negative marking
  • Please input correct details for the leaderboard

Leaderboard

RankNameCollegeQuantReasoningVerbalFinal Score
๐Ÿฅ‡MSNM1071027
๐ŸฅˆSatyajeet KumarNIT Rourkela1051025
๐Ÿฅ‰Ayush RajIIT K96924
4KanishkJSSATE106824
5AdityaIIT BHU96924
6S kiit d107724
7JashIIT BHU105823
8ProfessionalXYZ106723
9JxjcjBxjx106622
10SPARSHFORE97521
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Solutions

Please note that order might be different as questiosn ae randomized in the test

Quant Solutions

Sol : 1

Original Price = 200

Price after a 20% increase = 200+(20% of 200)=200+40=240

Price after a 10% discount on 240 = 240โˆ’(10% of 240)=240โˆ’24=216

Sol : 2

A=$5000 * (1+8/100โ€‹)^2 = 5000*(1.08)^2$

= 5000ร—1.1664 = 5832$

Sol : 3

Based on given ration, let number of boys, girls and teachers be 33x, 53x and 2x.

Given, 2x=10, so x=5

Number of students = (33x + 53x)=86ร—5=430

Sol : 4

Loss = CP – SP = 5400 – 4500 = 900

Loss % = 900/ 5400*100 = 16.67%

Sol: 5

Subtracting the two equations:

$x+y – (xโˆ’y)=12 – 4$

$2y = 8$

$y = 4$

Sol : 6

Let the five consecutive numbers be xโˆ’2, xโˆ’1, x, x+1 and x+2

Their average = x=15

Smallest number = xโˆ’2=13; and largest = x+2=17

Sum of smallest and largest = 13+17 = 30

Sol: 7

Convert the speed into km/hr first

Speed = 30m/s = 30*3600/1000 = 108 km/hr

Time = 240/108 = 2.22 hour

Sol : 8

Total work = 6 menร—8 days=48 man-days

For 4 men, days required = 48 /4 =12

Sol : 9

Use direct formula of area of circle = $\pi*r^2$

Sol: 10

Number of arrangements = 4!

Reasoning Solutions

Sol : 1

Z (26), Y (25), W (23), T (20), P (16)

The pattern is: -1, -2, -3, -4

Following the pattern, the next term will be Pโˆ’5=M

Sol : 2

Every letter is increased by 1

Sol : 3

The man is the son of Sarahโ€™s mother or father, which makes him Sarah’s brother.

Sol : 4

The problem states a clear requirement of 5 years of experience. Although Jane has the required qualification, she lacks the experience, so based on the strict criteria, she should not be selected.

Sol : 5

The statement implies that planning aids in success, but it doesnโ€™t imply exclusivity. Hence, assumption B is correct.

Sol : 6

U is second from the right, so position 5 is U.Since Q is between P and R, and S is to the left of T, the order is:

P – Q – R and S – T – U

With U in the fifth position, R must be on the right end (position 6).

Sol : 7

2024 is a leap year, so it has 366 days.

From February 15, 2024, to February 15, 2025, there are 366 days.

366 days = 52 weeks + 2 extra day. Thus, the day will shift by 2 days

Sol : 8

Starting at south, turns go as follows:

  1. Right to west
  2. Left to south
  3. Left to east

So, Sarah is facing east.

Sol : 9

Dots are moving by 90 degree in each step

Sol : 10

Assume B has x apples, A will have x + 4 and C will have 2x.

Solve to get x = 6

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