Aptitude Questions on Speed, Distance and Time
Review Speed, Distance and Time concepts
This page is packed with carefully crafted questions designed to build your skills in solving a range of questions on Speed, Distance and Time.
Q. 1 Imagine you’re planning a road trip between two beautiful cities, City A and City B. On the way there, your car cruises smoothly at 60 km/h, enjoying the scenic views. However, on the return trip, with lighter traffic, you manage to speed up to 90 km/h. Over the entire journey, what would be the car’s average speed?
A) 70 km/h
B) 72 km/h
C) 75 km/h
D) 78 km/h
Check Solution
Ans: B) 72 km/h
Average speed for a round trip = $\frac{2 \times \text{Speed}_1 \times \text{Speed}_2}{\text{Speed}_1 + \text{Speed}_2}$
= $\frac{2 \times 60 \times 90}{60 + 90} = \frac{10800}{150} = 72$ km/h.
Q. 2 Two high-speed trains begin their journey from towns A and B, 300 km apart, rushing towards each other on parallel tracks. Train A races at a speed of 60 km/h, while Train B zips along at 40 km/h. How much time will it take for the two trains to meet, assuming they started simultaneously?
A) 2.5 hours
B) 3 hours
C) 3.5 hours
D) 4 hours
Check Solution
Ans: B) 3 hours
Relative speed = 60 + 40 = 100 km/h.
Time taken = Distance / Relative speed = $\frac{300}{100} = 3$ hours.
Q. 3 A man enjoys a walk of 5 km/h and usually covers a certain distance in 4 hours. One day, inspired by a challenge, he decides to quicken his pace to 7 km/h. How much time does he save by walking faster?
A) 1 hour
B) 1.5 hours
C) 2 hours
D) 2.5 hours
Check Solution
Ans: A) 1 hour
Distance = Speed × Time = 5 × 4 = 20 km.
Time at new speed (7 km/h) = $\frac{20}{7} \approx 2.86$ hours.
Time saved = 4 – 2.86 = 1.14 hours (approximately 1 hour and 8 minutes).
Q. 4 A train, 150 meters in length, passes a pole in 15 seconds. What is the speed of the train in km/h?
A) 30 km/h
B) 36 km/h
C) 40 km/h
D) 54 km/h
Check Solution
Ans: B) 36 km/h
Speed = Distance / Time = $\frac{150}{15} = 10$ m/s.
Converting to km/h: $10 \times 3.6 = 36$ km/h.
Q. 5 A cyclist covers a certain distance in 40 minutes at 18 km/h. Later, he decides to increase his pace, hoping to complete the same journey in just 30 minutes. What should be his required speed?
A) 20 km/h
B) 21 km/h
C) 22 km/h
D) 24 km/h
Check Solution
Ans: D) 24 km/h
Distance = Speed × Time = $18 \times \frac{40}{60} = 12$ km.
New speed = Distance / New time = $\frac{12}{\frac{30}{60}} = \frac{12}{0.5} = 24$ km/h.
Q. 6 Picture a boat navigating a serene river. It takes 2 hours to travel 24 km downstream, aided by the current, but requires 3 hours to cover the same distance upstream against the flow. Can you determine the speed of the river’s current?
A) 2 km/h
B) 3 km/h
C) 4 km/h
D) 5 km/h
Check Solution
Ans: A) 2 km/h
Downstream speed = $\frac{24}{2} = 12$ km/h, Upstream speed = $\frac{24}{3} = 8$ km/h.
Speed of the stream = $\frac{\text{Downstream speed} – \text{Upstream speed}}{2} = \frac{12 – 8}{2} = 2$ km/h.
Q. 7 If a train running at 54 km/h crosses a platform in 36 seconds and a pole in 18 seconds, what is the length of the platform?
A) 150 meters
B) 200 meters
C) 240 meters
D) 300 meters
Check Solution
Ans: C) 240 meters
Train speed = 54 km/h = 15 m/s.
Length of train = 15 × 18 = 270 meters.
Total distance to cross platform = 15 × 36 = 540 meters.
Length of platform = 540 – 270 = 270 meters.
Q. 8 A rower paddles downstream for 12 km, completing the journey in 2 hours. On the way back, against the current, the same distance takes 3 hours. Determine the speed of the rower’s boat in still water?
A) 3 km/h
B) 4 km/h
C) 5 km/h
D) 6 km/h
Check Solution
Ans: C) 5 km/h
Downstream speed = $\frac{12}{2} = 6$ km/h, Upstream speed = $\frac{12}{3} = 4$ km/h.
Speed in still water = $\frac{\text{Downstream speed} + \text{Upstream speed}}{2} = \frac{6 + 4}{2} = 5$ km/h.
Q. 9 A man running at 10 km/h crosses a bridge of length 120 meters in 54 seconds. What is the length of the bridge?
A) 100 m
B) 120 m
C) 150
D) 180 m
Check Solution
Ans: C) 150 m
Convert speed to m/s: $10 \times \frac{1000}{3600} = \frac{25}{9}$ m/s.
Distance = Speed × Time = $\frac{25}{9} \times 54 = 150$ meters.
Q. 10 A car moving at 72 km/h overtakes a truck traveling at 54 km/h. If the car is 5 meters long and the truck is 15 meters long, how much time does the car take to pass the truck?
A) 4 seconds
B) 6 seconds
C) 8 seconds
D) 10 seconds
Check Solution
Ans: A) 4 seconds
Relative speed = 72 – 54 = 18 km/h = $18 \times \frac{5}{18} = 5$ m/s.
Total distance = 5 + 15 = 20 meters.
Time taken = $\frac{20}{5} = 4$ seconds.
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