Calendar and Clock: Reasoning Questions with Answers

Ans: A) Thursday

2025 is not a leap year, so it has 365 days. Hence, January 1, 2026, will be 365 days later, which is $365 \div 7 = 52$ weeks and 1 extra day.
So, the day will shift by 1 day: Wednesday + 1 = Thursday.

Ans: A) 0

For 1200 years:

• 800 years (leap years) contribute (800÷4=200×2)=400(800 \div 4 = 200 \times 2) = 400(800÷4=200×2)=400 odd days.
• 400 years contribute 0 odd days (as the Gregorian cycle repeats).

Thus, $400 + 0 = 400 \div 7 = 0$ odd days.

Ans: A) 1900

A year is a leap year if:

1. Divisible by 4.
2. Not divisible by 100, unless divisible by 400.

1900 is divisible by 100 but not by 400, so it is not a leap year.

Ans: A) 10°

At 4:20:

• Hour hand’s position: $4 \times 30 + \frac{20}{60} \times 30 = 120 + 10 = 130°$.
• Minute hand’s position: $20 \times 6 = 120°$

Angle = 130°−120°=10°.

Ans: A) 365

2022 is not a leap year. From March 3, 2022, to March 3, 2023, there are 365 days.

Ans: B) 2052

Leap years repeat every 28 years. Thus, 2024 + 28 = 2052.

Ans: C) 22

The hour and minute hands coincide once every hour, except at 12 o’clock. In a 12-hour cycle, this happens 11 times. Over 24 hours: $11 \times 2 = 22$

Ans: A) Monday

January 1, 2000, is Saturday (given). 2000 is a leap year.
So, January 1, 2001 = Saturday+2=Monday

Ans: A) 3:20

The time in the mirror = 12:00−8:40 = 3:20

Ans: D) Tuesday

100 days = $100 \div 7 = 14$ weeks + 2 days.
Sunday + 2 = Tuesday.

Ans: A

Every non leap year will have 1 odd day and every leap year will have 2 odd days. Considering this find out total numbe of odd days for in between years and add that with days between intial and final year (excluding in between year since you have already calculated oddd days for those years). You can also try other mental tricks like calculating difference between the dats for the same year and then shifting it by odd days for every year

Ans: A

Since a weekday repeats every 7 days, you need to divide no of days 20 by 7 to get remainder 6. Now count from Saturday for next 6 days

Ans: A

Weekdays will repeat in a cycle of 7. So divide the differnece of days 26 – 14 = 12 by 7 to get remainder 5. Now count after Saturday for next 5 days

Ans: A

Since a weekday repeats every 7 days, you need to divide no of days 11 +2 (to accommodate for day before yesterday by 7 to get remainder 6. Now count from Thursday for next 6 days

Ans: A

Weekdays will repeat in a cycle of 7. Now calculate the no of days passed by counting days for in between months and in the intial and the final month. You will get total no of days as = 116. Divide it by 7 to get remainder 4. Now count from Friday for next 4 days

Ans: A

Find out how many days passed till today from given date and divide the difference with 7 to get the remainder

Ans: A

Pick up one of the option and see what day falls on that date and then check for other options as the dates are next to each other